Diferencia entre revisiones de «Vibra: probs c1»
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'''If the system shown in fig. has m= 0.010kg and s= 36 N/m , calculate (a) the angular frequency, (b) the frequency, and (c) the period.''' | |||
(a) \begin{equation} | |||
F = \sqrt{s \over m} | |||
\end{equation} | |||
\begin{equation} | |||
f= \sqrt{36 \over 0.010} = 60 {s^{-1}} | |||
\end{equation} | |||
(b) \begin{equation} | |||
f = {1 \over 2\pi} \sqrt{s \over m} = 9.5 Hz | |||
\end{equation} | |||
(c) \begin{equation} | |||
T= { 2\pi} \sqrt{m \over s} = 0.10 s | |||
\end{equation} | |||
--[[Usuario:David Hernandez Leon|David Hernandez Leon]] ([[Usuario discusión:David Hernandez Leon|discusión]]) 22:00 4 may 2013 (CDT) | |||
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Revisión del 22:00 4 may 2013
Main cap.1
1.1 If the system shown in fig. has m= 0.010kg and s= 36 N/m , calculate (a) the angular frequency, (b) the frequency, and (c) the period.
(a) \begin{equation} F = \sqrt{s \over m} \end{equation}
\begin{equation} f= \sqrt{36 \over 0.010} = 60 {s^{-1}} \end{equation}
(b) \begin{equation} f = {1 \over 2\pi} \sqrt{s \over m} = 9.5 Hz \end{equation}
(c) \begin{equation} T= { 2\pi} \sqrt{m \over s} = 0.10 s \end{equation} --David Hernandez Leon (discusión) 22:00 4 may 2013 (CDT)
1.2